Tuesday, February 10, 2015

Zopper online assesment question on HackerEarth with solution.

Recently a friend asked me to solve a problem which he got on one of the interview, online assessment test. I decided to document my solution here. The companies name was Zopper and the question was asked on the initial online screening test on HackerEarth.


HackerMan says that 5 and 8 are smart digits. A positive integer is called a smart number if it has only smart digits in its decimal representation.
HackerMan has three sets of numbers. And he needs your help to find out the number of distinct smart numbers that he can make using one number from each of the three sets. You have to help in it
Note: You must not count the same smart number more than once.
  • The three sets will contain between 1 and 50 elements, inclusive.
  • Each number in the three sets will contain numbers between 1 and 30,000, inclusive.
Input Format
  • The first, third and fifth lines will contain a number N that will specify the count of numbers in the sets on the second, fourth and sixth lines of input.
  • The second, fourth and sixth line will contain the three sets of numbers respectively.
Output Format
Print a single line containing the count of distinct smart numbers.

Sample Input 
3 5 4
2 1 3
2 1 5
Sample Output 
We have two smart numbers 5 = 3 + 1 + 1 and 8 = 5 + 2 + 1. 8 can be also expressed as 4 + 2 + 2, but you must not count 8 twice.

Time Limit: 2 sec(s) for each input file.
Memory Limit: 256 MB
Source Limit: 1024 KB
Marking Scheme: Marks are awarded if any testcase passes.
Allowed languages: C, C++, Clojure, Go, Haskell, C#, Java, JavaScript, Objective-C, Perl, PHP, Python, Ruby


def assign_walls(row,col):
        w = raw_input()
        inp = w.split(" ")
        if inp[0] is 'C':

def main():
        sections = []
        row = []
        col = []
        row_counter = 0
        col_counter = 0
        row_section = [(0,MAX_ROW)]
        col_section = [(0,MAX_COL)]
        no_of_walls = raw_input()
        for i in range(int(no_of_walls)):
        #print row
        #print col
        for i in row:
                if(i < row_section[row_counter][1]):
                        row_end = row_section[row_counter][1]
                        row_start = row_section[row_counter][0]
                        row_section[row_counter] = (row_start,i)
                        row_counter = row_counter+1
        for i in col:
                if(i < col_section[col_counter][1]):
                        col_end = col_section[col_counter][1]
                        col_start = col_section[col_counter][0]
                        col_section[col_counter] = (col_start,i)
                        col_counter = col_counter+1
        #print row_section
        #print col_section
        for i in row_section:
                row_length = i[1]-i[0]
                #print row_length
                for j in col_section:
                        col_length = j[1]-j[0]
                        #print col_length
                        area = row_length*col_length
                        #print area
        return section_areas[len(section_areas)-1]

if __name__ == "__main__":
        out = []
        t = raw_input()
        for i in range(int(t)):
        for x in out: